Square Root Function Problems

In general, square root of an integer A is a number B such that B2 = A, and we also deliver it by another ways, a number B whose square is A. Every non-unenthusiastic real number A has a only one of its kind of non-unenthusiastic square root, is said to be as the principal square root root, defined by a square roots symbol as sqrt (x). For positive (+) A, the principal square root will also rewrite in exponent notation, as like A1/2. For e.g. Principal square root of 16 is 4, obtained by sqrt (16) = 4, because 42 = 4 × 4 = 16 and 4 is non-negative.

Different Functions of Square Root:

Square root in math having different properties they are described below,

General expression with exponent and radical: `(^nsqrt (a) ^m) =(^nsqrt (a)) ^m =(a1/n) ^m = a^m/n`

Multiplication property for radical expression: `(^nsqrt (ab))= (^nsqrt (a)) (^nsqrt (b))`

Division property for radical expression: `(^nsqrt (a/b)) = (^nsqrt (a)) / (^nsqrt (b))`

Square Root Function Problem:

Example for square root in math: Add: `(9 xx sqrt (5))-(6 xx sqrt (5)) + (8 xx sqrt (5))`

Solution: Unite like terms by adding together the numerical coefficients.

`(9 - 6 + 8) xx sqrt (5)`

`(17 - 6) xx sqrt (5)`

After adding together, we get the answer like,

`11 xx sqrt (5)`

Example for square root function:   Simplify `sqrt (81) + sqrt (9)`

Solution: Take the given question and split the terms like,

`sqrt (9 xx 9) + sqrt (3 * 3)`

Rewrite the square root by using product of square root theorem.

`sqrt (9) xx sqrt (9) + sqrt (3) xx sqrt (3)`

To simplify even further we use the definition of square root,

`= 9 + 3`

Simplify by adding like terms to get the answer

`= (9 + 3)`

`= 12`

Thus, `sqrt (81) + sqrt (9) = 12.`

Example for square root function: Solve `sqrt (2) xx sqrt (196) = sqrt (392)`

` = sqrt (2 xx 196)`

`= sqrt (2 xx 14^2)`

` = ^14 sqrt (2)`

Practice problem for square root function:

Problem for square root function: `(sqrt (121))`

Answer: `11`

Problem for square root function: `(sqrt (169))`

Answer: `13`

Problem for square root function: `(sqrt (2025))`

Answer: `45`

Problem for square root function: `sqrt (2) + sqrt (4)`

Answer: `2 sqrt (2)`

Trig Ratio Table

Special angles comprise trigonometric values that may be considered exactly. The special angle values can be calculated using trigonometric ratios. Specifically, the angles of 0, 30, 45, 60, 90 degrees are the special ones. Right angles include the measure as 90 degree. A right triangle consists of a Right Angle as one of its 3 angles. The right triangles consist of two special triangles which are 30-60-90 right triangle and 45-45-90 right triangle. Let us see about the trig ratio table.

Trig Ratio Table

Followings are the six trigonometric ratios

Sin θ = `(opposite)/("hypotenuse")`

Cos θ = `(adjacent)/("hypotenuse")`

Tan θ = `(opposite)/(adjacent)`

Cosec θ = `("hypotenuse")/(opposite)`

Sec θ = `("hypotenuse")/(adjacent)`

Cot θ = `(adjacent)/(opposite)`

Trig ratio table

Example

Evaluate 46 sin 30˚ + 16 cos 60˚ - 8 tan 45˚

Solution

46 sin 30˚ + 16 cos 60˚ - 8 tan 45˚

46 x `1/2`   + 16 x `1/2`  - 8

23+ 8 -8

31 - 8 = 23

46 sin 30˚ + 16 cos 60˚ - 8 tan 45˚ = 23

Examples for Trig Ratio Table

Example 1 for trig ratio table

Find the adjacent side of the right angle triangle if angle θ is 60°, and the hypotenuse is 24.

Solution:

Cos θ =`(adjacent)/("hypotenuse")`

Given

Given θ is 60 degree

Hypotenuse side = 24

Assume adjacent side = x

Cos 600 =  `x/24`

x=   `24 xx cos 60^0`

x =  `24xx(1/2)`

x = 24 x 0.5        {Value of cos 60 degree`1/2` }

x = 12

Therefore, the adjacent side of the right angle triangle = 12

Example 2 for trig ratio table

Evaluate 18 sin 30˚ + 16 cos 60˚ - 8 tan 45˚

Solution

18 sin 30˚ + 16 cos 60˚ - 8 tan 45˚

18 x `1/2`   + 16 x `1/2`  - 8

9+ 8 -8

17 - 8 = 9

18 sin 30˚ + 16 cos 60˚ - 8 tan 45˚ = 9

Example 3 for trig ratio table

Evaluate 28 sin 30˚ + 16 cos 60˚ - 8 tan 45˚

Solution

28 sin 30˚ + 16 cos 60˚ - 8 tan 45˚

28 x `1/2`   + 16 x `1/2`  - 8

14+ 8 -8

22 - 8 = 14

28 sin 30˚ + 16 cos 60˚ - 8 tan 45˚ = 14

Example 4 for trig ratio table

Evaluate 12 cosec 30˚ + 16 sec 60˚ - 8 cot 45˚

Solution

12 cosec 30˚ + 16 sec 60˚ - 8 cot 45˚

12 x 2 + 16 x 2- 8

24+ 32 -8

56 - 8 = 48

12 cosec 30˚ + 16 sec 60˚ - 8 cot 45˚ = 48

Example 5 for trig ratio table

Evaluate 7 cosec 30˚ + 16 sec 60˚ - 8 cot 45˚

Solution

7 cosec 30˚ + 16 sec 60˚ - 8 cot 45˚

7 x 2 + 16 x 2- 8

14+ 32 -8

46 - 8 = 38

7 cosec 30˚ + 16 sec 60˚ - 8 cot 45˚ = 38

Use of Calculus in Real Life

In this article we are going to discuss about the use of calculus in real life problems step by step concept. The process of contraction the calculus comparable to over screening the real life problems concept and problem in calculus are referred as review use of calculus in real life. This article helps to improve the knowledge the real life for calculus and below the problems are using toll for the help with test calculus. Put down behind the useful get review real life use of calculus to this article. Use of calculus in real life solutions also show below.

Level One Example Real Life Calculus Use Problems:-

Real life calculus use problem 1:-

Integrate the following equation

`int 5x^4+4x^5+5x^3 dx`

Solution:-

Step 1:-

`int 5x^4+4x^5+3x^3 dx`

Step 2:-

`= int5x^4dx + int4x^5dx + int 3 x^3 dx`

Integrating the above equation

We get

Step 3:-

`= (5x^5)/(5) + (4x^6)/ (6) + (3x^4)/ (4)`

Step 4:-

`= (5x^5)/(5) + (4x^6)/(6) +(3x^4)/ (4)`

Step 5:-

`= x^5+ (2x^6)/ (3) + (3x^4)/ (4)`


Real life calculus use problem 2:-

Solve by differentiating the following equation and get the first derivative second derivative and third derivative

`y = 12x^3 + 8x^2+ 4x^5 + x`

Solution:-

Given equation is `y = 12x^3+ 8x^2 + 4x^5 + x`

Step 1:-

To get the 1st derivative differentiate the above given equation

`(dy)/(dx) = 36x^2+16x+20x^4`

Step 2:-

To get the 2nd derivative differentiate the ist derivative

`(d^2y)/ (dx^2) = 72x+16+80x^3.`


Level Two Example Real Life Calculus Use Problems:-

Real life calculus use problem 1:-

Integrate the following equation

`int 8x^4+4x^5+2x^3 dx`

Solution:-

`int 8x^4+4x^5+2x^3 dx`

Step 1:-

`= int 8x^4 dx + int 4x^5 dx + int 2 x^3 dx`

Integrating the above equation

We get

Step 2:-

`= (8x^5)/ (5) + (4x^6)/ (6) + (2x^4)/ (4)`

Step 3:-

`= (8x^5)/(5) + (2x^6)/(3)+ (x^4)/(2)`

Real life calculus use problem 2:-

Differentiate the following equation and get the 1st, 2nd and 3rd derived

`y = 8x^3+4x^2+2x^1+ 12`

Solution:-

Step 1:-

By differentiate the given equation with respect to x to get the 1st derivative

`y= dy/dx =24x^2+8x^1+2.`

Step 2:-

To get the 2nd derived differentiate the 1st derivative of the given equation.

`y = (d^2x)/ (dy^2) = 48x + 8`

Step 3:-

To get the 3rd derived differentiate the 2nd derivative of the given equation.

`y= (d^3x)/ (dy^3) = 48.`

Function of X Graph

In the mathematics concept, a polynomial function is an expression of finite measurement, lengthwise it is constructed from variables and constant values, using only the operations of addition, subtraction, multiplication, and non-negative, whole-number exponent values. For example, 3x2 − 5x + 9 is a polynomial, but 3/x2 − 5/x + 9x3/2 is not, because its second term involves division by the variable x and because its third term contains an exponent that is not a whole number. In this article we shall discuss about function of x graph.

Sample Problem for Function of X Graph:

Problem 1:

Solve the function f(x) = 2 x + 3.find the coordinate of vertex of the triangle formed by lines and the x axis in graphing polynomial.

Solution:

Given:

        F(x) = 2x + 3

We take f(x) = -y

We get,   2 x – y + 3 = 0

        Thus, 2x – y = -3

                        2x = y – 3

Equation (1) is divided by -1. We get

                              -2x = -y + 3

                              y = 2x + 3 -------------- (1)


From equation (1) we get the following values

            X         -2         -1           0        1

            Y          -1          1          3         5

Problem 2:

Solve the function f(x) = -x + 4.find the coordinate of vertex of the triangle formed by lines and the x axis in graphing polynomial.

Solution:

Given:

        F(x) = -x + 4

We take f(x) = y

We get,   -x + y + 4 = 0

        Thus, -x + y = -4

                        -x = -y – 4

                         y = x - 4

From equation (1) we get the following values

            X      0            1           2           3

            Y     -4           -3          -2           -1

Function of X Graph:problem 3:

Solve the function f(x) = -2 x - 3.find the coordinate of vertex of the triangle formed by lines and the x axis in graphing polynomial.

Solution:

Given:

        F(x) = -2x - 3

We take f(x) = -y

We get,   -2 x - y - 3 = 0

        Thus, -2x - y = 3

                          -2x = y + 3

Equation (1) is divided by -1. We get

                              2x = -y -3

                              y = -2x - 3 -------------- (1)

From equation (1) we get the following values

            X         -2         -1       0            1          

            Y          1         -1      -3           -5

     

Quadrilateral Right Angle

Quadrilateral is a two dimensional figure which has four sides and four inside angles. In Quadrilateral, All sides are equal lengths and equal angles. It is also called as four sided polygon with four angles. Quadrilateral is a type of plane geometry. There are many quadrilaterals in geometry. They are square, rectangle, rhombus, and parallelogram, and kite, trapezoid. Let us learn about the right angle quadrilaterals.



Quadrilateral Right Angle:



An internal angle that is equal to 90° is said to be right angle.



These are various kinds of right angles.

Various properties of Quadrilateral:

• All quadrilaterals contain 4 surfaces.
• A square has acquired 4 surfaces of identical length and 4 right angles.
• A Rhombus has acquired 4 sides of identical length and opposite sides is parallel and angles are identical.
• The rectangle holds 4 right angles. It has acquired 2 pairs of identical length surface.
• A trapezium has acquired one pair of parallel sides.
• A kite has acquired two pairs of surface next to each other that have identical length.

Types of Quadrilaterals with Right Angles:

Square:



A square has equivalent surface and each angle is a right angle. As well as, opposite surface are parallel.

Rectangle:



Rectangle is a shape with 4 sides where each angle is a right angle. As well as, differing surface are parallel and of identical length.

Rhombus:



A rhombus is figure with 4 sides where all surface have identical length. Rhombus does not have the right angle. But the diagonal got right angles. Also differing surface are parallel and opposite angles are identical.

Kite:



It has two pair of surface. Every pair is prepared up of adjacent sides that are identical in length. The angles are equivalent where the pairs get together. Diagonals get together at a right angle, and one of the diagonal bisects another.

Trapezium:



Both of these are kind of trapezium. Every of them have dissimilar properties in the quantity of right angles. But each have 4 surface and one pair of parallel surface.

Set Multiple Values

The definition of set is group of object. Collection of whole number, collection of natural numbers, and collection of fraction numbers it is called the some examples of set multiple values. The set symbol is represented the { }. The example of set multiple value is {4, 5, 7, 6}. Next we discuss about this articles set multiple values.

First Problem of Set Multiple Values

Problem 1: set multiple values

If A = {5, 3, 6, 2, 7, 13 ,15} and B  = {5, 3, 6, 2, 7}  find out n(A), n(B), n(A `uu` B)and n(A `nn` B) and to prove n (A `uu`B) = n (A) + n (B) – n (A `nn`B)

Solution:

A = {5, 3, 6, 2, 7, 13, 15}

B = {5, 3, 6, 2, 7}

A `uu` B = {5, 3, 6, 2, 7, 13, 15}

A `nn` B = {5, 3, 6, 2, 7}

n (A) = 7

n (B) = {5},

n (A`uu` B) = {7},

n (A`nn` B} = {5}

n (A) + n (B) – n (A `nn` B)

7 + 5 - 5

= 7

The A `uu` B = 7

So,

n (A`uu` B) = n (A) + n (B) – n (A `nn` B)

Second Problem of Set Multiple Values

Problem 2: set multiple values

If X = {7, 9, 4, 2, 5} and Y = {7, 9, 4, 2, 5, 13, 14} find n(X), n(Y) n(X `uu` Y), n(X `nn` Y) and to verify the identity n (X uu Y) = n (X) + n (Y) – n (X `nn` Y)

Solution:

X = {7, 9, 4, 2, 5}

Y = {7, 9, 4, 2, 5, 13, 14}

{X `uu` Y} = {7, 9, 4, 2, 5, 13, 14}

{X `nn` Y} = {7, 9, 4, 2, 5}

n (X) = {5}

n (Y) = {7}

n(X `uu` Y) = {7}

n(X `nn` Y) = {5}

n (X) + n (Y) – n (X `nn` Y)

= 5 + 7- 5

= 12 - 5

= 7

Here X `uu` Y = 7

So,

n (X`uu` Y) = n (X) + n (Y) – n (X `nn` Y)

Place Value Tenths Hundredths

Place value can describe the value of all numbers .The place value can be used to point out the position of a mathematical system. It is tremendously helps you to read the numerals by its places. Place value is the value which is given to the digit by popular quality .In this article we shall discuss the place value of tenths hundredths.

Place Value Tenths Hundredths:

The place values from one to ten thousand and to ten thousandth are as follows.

For example for the value 11111.11111

1 – Place value one.

10 = place value Ten.

100 – Place value Hundred.

1000 – Place value thousand.

10000 – Place value ten thousand.

1÷10 =0.1- place value tenth.

1÷100= 0.01- place value hundredth.

1÷1000=0.001- place value thousandth.

1÷10000=0.0001- place value ten thousandth.

1÷100000=0.00001- place value hundred thousandth.

Examples Problems on Place Value:

Ex:1 Round the following number to the hundredth place value 746.839256

Sol:

Given that the number 746.839256

From the given number on the left side from the decimal point,

7 indicates Place value Hundred.

4 indicate place value ten.

6 indicate Place value one.

From the given number on the right side from the decimal point,

8 indicate tenth place value.

3 indicate hundredth place value.

9 indicate thousandth place value.

2 indicate ten thousandth place value and so on.

As the question is to encircle the number 746.839256 to the hundredth place value.

The answer is 746.83

Ex:2 Add the numbers 1563.457 and 1999.336 and round the solution to the hundredth place value.

Sol:

Adding the numbers we get




The solution is  3562.793

From the given number on the left side from the decimal point,

3 indicate place value thousand.

5 indicate Place value Hundred.

6 indicate place value ten.

2 indicate Place value one.

From the given number on the right side from the decimal point,

7 indicate tenth place value.

9 indicate hundredth place value.

3 indicate thousandth place value.

As the question is to encircle the number 3562.793 to the tenth place value.

The answer is 3562.8 because the place value nearest to hundredth (7) is greater than 5(9).


Ex:3 Round the following number to the tenth place value 876.473957

Sol:

Given that the number 876.473957

From the given number on the left side from the decimal point,

8 indicates Place value Hundred.

7 indicate place value ten.

6 indicate Place value one.

From the given number on the right side from the decimal point,

4 indicate tenth place value.

7 indicate hundredth place value.

3 indicate thousandth place value.

9 indicate ten thousandth place value and so on.

As the question is to encircle the number 876.473957to the tenth place value.

The answer is 876.5

Ex:4 Add 388.8018 and 100.1111 and round the solution to tenth place value.

Sol:

Adding 388.8018 and 100.1111 we get,



The solution is  488.9129

From the given number on the left side from the decimal point,

4 indicate Place value Hundred.

8 indicate place value ten.

8 indicate Place value one.

From the given number on the right side from the decimal point,

9 indicate tenth place value.

1 indicate hundredth place value.

2 indicate thousandth place value.

9 indicate ten thousandth place value.

As the question is to encircle the number 488.9129 to the tenth place value.

The answer is 488.9

Practice Problems on Place Value:

Q:1 Round the following number to the hundredth place value 44776.76234

Ans:

The answer is 44776.76

Q:2 Round the following number to the tenth place value 56256353.3564847

Ans:

The answer is 56256353.4